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  5. Uploading An Image

Uploading An Image

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G
Grimloch
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Senior Member

I have a very simple question that I'm not sure of an answer to. Is it possible to use the image upload function in 'INCLUDES/infusions_include.php' to upload an image just by providing a $_POST['image_name'] variable?
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douwe_yntema
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answered
Senior Member

According to the documentation you need at least also specify a destination folder:


https://www.php-fusion.co.uk/infusion...40#page414
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C
Chan
C
Chan 0
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answered
Super Admin

Actually, no. Those upload_file and upload_image function uses $_FILES, not $_POST.

If you use $_POST, I assume your file/image is already uploaded in the server and need to be moved to a specific folder instead?
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G
Grimloch
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Energy can neither be created nor destroyed; only transformed !
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answered
Senior Member

I know about the difference between $_POST and $_FILES. I tried using a call to 'INCLUDES/infusions_include' but could not make it work so I used an older routine from one of my other infusions and it now works great. I had to do a $_POST upload YES or NO and then call my upload routine with $_FILES. Here is my code:
Code Download source
if(isset($_POST['upload']) && ($_POST['upload']) == "yes") {
   include INFUSIONS."event_cal_panel/include/upload_image.php";
} else {
$event_pic = "";
$event_thb = "";
}

... and here is my upload routine:
Code Download source
$max_width = 1024;
$max_height = 768;
$max_tn_size = 110;
$max_pics = 1;
$newpic = $_FILES['event_pic'];
$newname_string="pic_".mt_rand(15000,1500000);
$imginfo = getimagesize($newpic['tmp_name']); 
if($imginfo[2]<1 || $imginfo[2]>3) $error='Wrong file type!';
if(!$error) {
if($imginfo[2]==1) {
 $tmpimg=ImageCreateFromGIF($newpic['tmp_name']);
 $filetype = ".gif";
 }
elseif($imginfo[2]==2) {
 $tmpimg=ImageCreateFromJPEG($newpic['tmp_name']);
 $filetype = ".jpg";
 }
elseif($imginfo[2]==3) {
 $tmpimg=ImageCreateFromPNG($newpic['tmp_name']);
 $filetype = ".png";
 }
if($imginfo[0]>$max_width || $imginfo[1]>$max_height) {
 if($imginfo[0]<$imginfo[1]) {
 $new_width = intval($imginfo[0]/($imginfo[1]/$max_height));
 $new_height = $max_height;
 }
 elseif($imginfo[1]<$imginfo[0]) {
 $new_height = intval($imginfo[1]/($imginfo[0]/$max_width));
 $new_width = $max_width;
 }
 else { $new_width=$max_width; $new_height=$max_height; }
} else {$new_width=$imginfo[0]; $new_height=$imginfo[1]; }
$newimg=imagecreatetruecolor($new_width,$new_height);
ImageCopyResized($newimg,$tmpimg,0,0,0,0,$new_width,$new_height,$imginfo[0],$imginfo[1]); 
ImageJPEG($newimg,PICPATH.$newname_string.".jpg");
$imginfo = getimagesize(PICPATH.$newname_string.".jpg");
$tmpimg=ImageCreateFromJPEG(PICPATH.$newname_string.".jpg");
if($imginfo[0]<$imginfo[1]) {
$new_width = $imginfo[0]/($imginfo[1]/$max_tn_size);
$new_height = $max_tn_size;
}
elseif($imginfo[1]<$imginfo[0]) {
$new_height = $imginfo[1]/($imginfo[0]/$max_tn_size);
$new_width = $max_tn_size;
}
else { $new_width=$max_tn_size; $new_height=$max_tn_size; }
$newimg=imagecreatetruecolor($new_width,$new_height);
ImageCopyResized($newimg,$tmpimg,0,0,0,0,$new_width,$new_height,$imginfo[0],$imginfo[1]); 
ImageJPEG($newimg,THBPATH.$newname_string."_thb.jpg");
   }
if($imginfo[2]==1) {
$event_pic = $newname_string.".gif";
$event_thb = $newname_string."_thb.gif";
}
elseif($imginfo[2]==2) {
$event_pic = $newname_string.".jpg";
$event_thb = $newname_string."_thb.jpg";
}
elseif($imginfo[2]==3) {
$event_pic = $newname_string.".png";
$event_thb = $newname_string."_thb.png";
}
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G
Grimloch
G
Energy can neither be created nor destroyed; only transformed !
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answered
Senior Member

I've encountered a slight glitch. I want to upload the image without renaming so I tried this:
Code Download source
$newpic = $_FILES['event_pic'];
$mypic = substr($newpic, 0, strrpos($newpic, "."));
$newname_string="$mypic";

It gives me this error.:
Code Download source
strrpos() expects parameter 1 to be string, array given

How do I first convert the $_FILES array value(the uploaded filename) to a string so I can use this function?
0 replies
G
Grimloch
G
Energy can neither be created nor destroyed; only transformed !
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answered
Senior Member

I really think I must be getting senile...!!! The answer is really simple:
Code Download source
$mypic = substr($newpic['name'], 0, strrpos($newpic['name'], "."));
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Code Snippet and functions - 9

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C
Chan 0
Lead Developer of PHP-Fusion
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G
G
Energy can neither be created nor destroyed; only transformed !
  • Senior Member, joined since
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  • Started 141 threads in the forums
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D
D
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